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(3x-1)(5x+2)=168
We move all terms to the left:
(3x-1)(5x+2)-(168)=0
We multiply parentheses ..
(+15x^2+6x-5x-2)-168=0
We get rid of parentheses
15x^2+6x-5x-2-168=0
We add all the numbers together, and all the variables
15x^2+x-170=0
a = 15; b = 1; c = -170;
Δ = b2-4ac
Δ = 12-4·15·(-170)
Δ = 10201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{10201}=101$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-101}{2*15}=\frac{-102}{30} =-3+2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+101}{2*15}=\frac{100}{30} =3+1/3 $
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