(3x-1)+(4x+2)+(10x-8)=180

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Solution for (3x-1)+(4x+2)+(10x-8)=180 equation: 



(3x-1)+(4x+2)+(10x-8)=180

We move all terms to the left:

(3x-1)+(4x+2)+(10x-8)-(180)=0

We get rid of parentheses

3x+4x+10x-1+2-8-180=0

We add all the numbers together, and all the variables

17x-187=0

We move all terms containing x to the left, all other terms to the right

17x=187

x=187/17

x=11

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