(3x-1)-4(x+2)=20-3(5-2x)

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Solution for (3x-1)-4(x+2)=20-3(5-2x) equation: 



(3x-1)-4(x+2)=20-3(5-2x)

We move all terms to the left:

(3x-1)-4(x+2)-(20-3(5-2x))=0

We add all the numbers together, and all the variables

(3x-1)-4(x+2)-(20-3(-2x+5))=0

We multiply parentheses

(3x-1)-4x-(20-3(-2x+5))-8=0

We get rid of parentheses

3x-4x-(20-3(-2x+5))-1-8=0



We calculate terms in parentheses: -(20-3(-2x+5)), so:

20-3(-2x+5)

determiningTheFunctionDomain
-3(-2x+5)+20

We multiply parentheses

6x-15+20

We add all the numbers together, and all the variables

6x+5

Back to the equation:

-(6x+5)



We add all the numbers together, and all the variables

-1x-(6x+5)-9=0

We get rid of parentheses

-1x-6x-5-9=0

We add all the numbers together, and all the variables

-7x-14=0

We move all terms containing x to the left, all other terms to the right

-7x=14

x=14/-7

x=-2

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