(3x-1)/(2x+4)=(x+1)/(5)

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Solution for (3x-1)/(2x+4)=(x+1)/(5) equation:


D( x )

2*x+4 = 0

2*x+4 = 0

2*x+4 = 0

2*x+4 = 0 // - 4

2*x = -4 // : 2

x = -4/2

x = -2

x in (-oo:-2) U (-2:+oo)

(3*x-1)/(2*x+4) = (x+1)/5 // - (x+1)/5

(3*x-1)/(2*x+4)-((x+1)/5) = 0

(3*x-1)/(2*x+4)+(-1*(x+1))/5 = 0

(5*(3*x-1))/(5*(2*x+4))+(-1*(x+1)*(2*x+4))/(5*(2*x+4)) = 0

5*(3*x-1)-1*(x+1)*(2*x+4) = 0

9*x-2*x^2-9 = 0

9*x-2*x^2-9 = 0

9*x-2*x^2-9 = 0

DELTA = 9^2-(-9*(-2)*4)

DELTA = 9

DELTA > 0

x = (9^(1/2)-9)/(-2*2) or x = (-9^(1/2)-9)/(-2*2)

x = 3/2 or x = 3

(x-3/2)*(x-3) = 0

((x-3/2)*(x-3))/(5*(2*x+4)) = 0

((x-3/2)*(x-3))/(5*(2*x+4)) = 0 // * 5*(2*x+4)

(x-3/2)*(x-3) = 0

( x-3/2 )

x-3/2 = 0 // + 3/2

x = 3/2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { 3/2, 3 }

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