(3x-1)/(3x+1)-(3x+1)/(3x+1)=3/2

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Solution for (3x-1)/(3x+1)-(3x+1)/(3x+1)=3/2 equation: 



(3x-1)/(3x+1)-(3x+1)/(3x+1)=3/2

We move all terms to the left:

(3x-1)/(3x+1)-(3x+1)/(3x+1)-(3/2)=0



Domain of the equation: (3x+1)!=0

We move all terms containing x to the left, all other terms to the right

3x!=-1

x!=-1/3

x!=-1/3

x∈R



We add all the numbers together, and all the variables

(3x-1)/(3x+1)-(3x+1)/(3x+1)-(+3/2)=0

We get rid of parentheses

(3x-1)/(3x+1)-(3x+1)/(3x+1)-3/2=0

Fractions to decimals

(3x-1)/(3x+1)+1-3/2=0

We calculate fractions


(6x-2)/(6x+2)+(-9x-3)/(6x+2)+1=0

We multiply all the terms by the denominator


(6x-2)+(-9x-3)+1*(6x+2)=0

We get rid of parentheses

6x-9x+1*(6x+2)-2-3=0

We add all the numbers together, and all the variables

-3x+1*(6x+2)-5=0

We move all terms containing x to the left, all other terms to the right

-3x+1*(6x+2)=5

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