(3x-1)/2=(5x+2)/3+1

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Solution for (3x-1)/2=(5x+2)/3+1 equation:



(3x-1)/2=(5x+2)/3+1
We move all terms to the left:
(3x-1)/2-((5x+2)/3+1)=0
We calculate fractions
(9x-3)/()+(-((5x+2)*2)/()=0
We calculate terms in parentheses: +(-((5x+2)*2)/(), so:
-((5x+2)*2)/(
We multiply all the terms by the denominator
-((5x+2)*2)
We calculate terms in parentheses: -((5x+2)*2), so:
(5x+2)*2
We multiply parentheses
10x+4
Back to the equation:
-(10x+4)
We get rid of parentheses
-10x-4
Back to the equation:
+(-10x-4)
We get rid of parentheses
(9x-3)/()-10x-4=0
We multiply all the terms by the denominator
(9x-3)-10x*()-4*()=0
We add all the numbers together, and all the variables
(9x-3)-10x*()=0
We get rid of parentheses
9x-10x*()-3=0
We move all terms containing x to the left, all other terms to the right
9x-10x*()=3

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