(3x-1)/2=(5x-4)/3

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Solution for (3x-1)/2=(5x-4)/3 equation: 



(3x-1)/2=(5x-4)/3

We move all terms to the left:

(3x-1)/2-((5x-4)/3)=0

We calculate fractions


3x/()+(-((5x-4)*2)/()=0



We calculate terms in parentheses: +(-((5x-4)*2)/(), so:

-((5x-4)*2)/(

We multiply all the terms by the denominator


-((5x-4)*2)



We calculate terms in parentheses: -((5x-4)*2), so:

(5x-4)*2

We multiply parentheses

10x-8

Back to the equation:

-(10x-8)



We get rid of parentheses

-10x+8

Back to the equation:

+(-10x+8)



We get rid of parentheses

3x/()-10x+8=0

We multiply all the terms by the denominator


3x-10x*()+8*()=0

We add all the numbers together, and all the variables

3x-10x*()=0

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