(3x-1)/2=(8x-4)/3

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Solution for (3x-1)/2=(8x-4)/3 equation:



(3x-1)/2=(8x-4)/3
We move all terms to the left:
(3x-1)/2-((8x-4)/3)=0
We calculate fractions
3x/()+(-((8x-4)*2)/()=0
We calculate terms in parentheses: +(-((8x-4)*2)/(), so:
-((8x-4)*2)/(
We multiply all the terms by the denominator
-((8x-4)*2)
We calculate terms in parentheses: -((8x-4)*2), so:
(8x-4)*2
We multiply parentheses
16x-8
Back to the equation:
-(16x-8)
We get rid of parentheses
-16x+8
Back to the equation:
+(-16x+8)
We get rid of parentheses
3x/()-16x+8=0
We multiply all the terms by the denominator
3x-16x*()+8*()=0
We add all the numbers together, and all the variables
3x-16x*()=0

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