(3x-1)/2=(x+4)/5

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Solution for (3x-1)/2=(x+4)/5 equation: 



(3x-1)/2=(x+4)/5

We move all terms to the left:

(3x-1)/2-((x+4)/5)=0

We calculate fractions


3x/()+(-((x+4)*2)/()=0



We calculate terms in parentheses: +(-((x+4)*2)/(), so:

-((x+4)*2)/(

We multiply all the terms by the denominator


-((x+4)*2)



We calculate terms in parentheses: -((x+4)*2), so:

(x+4)*2

We multiply parentheses

2x+8

Back to the equation:

-(2x+8)



We get rid of parentheses

-2x-8

Back to the equation:

+(-2x-8)



We get rid of parentheses

3x/()-2x-8=0

We multiply all the terms by the denominator


3x-2x*()-8*()=0

We add all the numbers together, and all the variables

3x-2x*()=0

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