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(3x-1)/2=(x+4)/5
We move all terms to the left:
(3x-1)/2-((x+4)/5)=0
We calculate fractions
3x/()+(-((x+4)*2)/()=0
We calculate terms in parentheses: +(-((x+4)*2)/(), so:We get rid of parentheses
-((x+4)*2)/(
We multiply all the terms by the denominator
-((x+4)*2)
We calculate terms in parentheses: -((x+4)*2), so:We get rid of parentheses
(x+4)*2
We multiply parentheses
2x+8
Back to the equation:
-(2x+8)
-2x-8
Back to the equation:
+(-2x-8)
3x/()-2x-8=0
We multiply all the terms by the denominator
3x-2x*()-8*()=0
We add all the numbers together, and all the variables
3x-2x*()=0
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