(3x-1)/4-(2x+1)/5=(7x-13)/20

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Solution for (3x-1)/4-(2x+1)/5=(7x-13)/20 equation: 


x in (-oo:+oo)

(3*x-1)/4-((2*x+1)/5) = (7*x-13)/20 // - (7*x-13)/20

(3*x-1)/4-((2*x+1)/5)-((7*x-13)/20) = 0

(3*x-1)/4+(-1*(2*x+1))/5+(-1*(7*x-13))/20 = 0

(5*20*(3*x-1))/(4*5*20)+(-1*4*20*(2*x+1))/(4*5*20)+(-1*4*5*(7*x-13))/(4*5*20) = 0

5*20*(3*x-1)-1*4*20*(2*x+1)-1*4*5*(7*x-13) = 0

140*x-140*x-180+260 = 0

80 = 0

80/(4*5*20) = 0

80/(4*5*20) = 0 // * 4*5*20

80 = 0

x belongs to the empty set

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