(3x-1)/4=(4x-2)/5

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Solution for (3x-1)/4=(4x-2)/5 equation: 



(3x-1)/4=(4x-2)/5

We move all terms to the left:

(3x-1)/4-((4x-2)/5)=0

We calculate fractions


3x/()+(-((4x-2)*4)/()=0



We calculate terms in parentheses: +(-((4x-2)*4)/(), so:

-((4x-2)*4)/(

We multiply all the terms by the denominator


-((4x-2)*4)



We calculate terms in parentheses: -((4x-2)*4), so:

(4x-2)*4

We multiply parentheses

16x-8

Back to the equation:

-(16x-8)



We get rid of parentheses

-16x+8

Back to the equation:

+(-16x+8)



We get rid of parentheses

3x/()-16x+8=0

We multiply all the terms by the denominator


3x-16x*()+8*()=0

We add all the numbers together, and all the variables

3x-16x*()=0

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