(3x-1)/8=(x+9)/4

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Solution for (3x-1)/8=(x+9)/4 equation: 



(3x-1)/8=(x+9)/4

We move all terms to the left:

(3x-1)/8-((x+9)/4)=0

We calculate fractions


3x/()+(-((x+9)*8)/()=0



We calculate terms in parentheses: +(-((x+9)*8)/(), so:

-((x+9)*8)/(

We multiply all the terms by the denominator


-((x+9)*8)



We calculate terms in parentheses: -((x+9)*8), so:

(x+9)*8

We multiply parentheses

8x+72

Back to the equation:

-(8x+72)



We get rid of parentheses

-8x-72

Back to the equation:

+(-8x-72)



We get rid of parentheses

3x/()-8x-72=0

We multiply all the terms by the denominator


3x-8x*()-72*()=0

We add all the numbers together, and all the variables

3x-8x*()=0

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