(3x-1)/x-2=3x+6/x+3

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Solution for (3x-1)/x-2=3x+6/x+3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x-1)/x-2 = 3*x+6/x+3 // - 3*x+6/x+3

(3*x-1)/x-(3*x)-(6/x)-3-2 = 0

(3*x-1)/x-3*x-6*x^-1-3-2 = 0

(3*x-1)/x-3*x-6/x-3-2 = 0

(3*x-1)/x+(-3*x*x)/x-6/x+(-3*x)/x+(-2*x)/x = 0

3*x-3*x*x-3*x-2*x-6-1 = 0

3*x-3*x^2-3*x-2*x-6-1 = 0

3*x-3*x^2-3*x-2*x-7 = 0

-3*x^2-2*x-7 = 0

-3*x^2-2*x-7 = 0

-1*(3*x^2+2*x+7) = 0

3*x^2+2*x+7 = 0

DELTA = 2^2-(3*4*7)

DELTA = -80

DELTA < 0

-1 = 0

-1/x = 0

-1/x = 0 // * x

-1 = 0

x belongs to the empty set

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