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(3x-10)+(2x+20)=90
We move all terms to the left:
(3x-10)+(2x+20)-(90)=0
We get rid of parentheses
3x+2x-10+20-90=0
We add all the numbers together, and all the variables
5x-80=0
We move all terms containing x to the left, all other terms to the right
5x=80
x=80/5
x=16
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