(3x-10)+(3x-10)+(2x)+(2x)+(3x+6)=180

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Solution for (3x-10)+(3x-10)+(2x)+(2x)+(3x+6)=180 equation:



(3x-10)+(3x-10)+(2x)+(2x)+(3x+6)=180
We move all terms to the left:
(3x-10)+(3x-10)+(2x)+(2x)+(3x+6)-(180)=0
We add all the numbers together, and all the variables
4x+(3x-10)+(3x-10)+(3x+6)-180=0
We get rid of parentheses
4x+3x+3x+3x-10-10+6-180=0
We add all the numbers together, and all the variables
13x-194=0
We move all terms containing x to the left, all other terms to the right
13x=194
x=194/13
x=14+12/13

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