(3x-10)+(3x-26)=180

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Solution for (3x-10)+(3x-26)=180 equation: 



(3x-10)+(3x-26)=180

We move all terms to the left:

(3x-10)+(3x-26)-(180)=0

We get rid of parentheses

3x+3x-10-26-180=0

We add all the numbers together, and all the variables

6x-216=0

We move all terms containing x to the left, all other terms to the right

6x=216

x=216/6

x=36

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