(3x-10)+(4x-31)=90

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Solution for (3x-10)+(4x-31)=90 equation: 



(3x-10)+(4x-31)=90

We move all terms to the left:

(3x-10)+(4x-31)-(90)=0

We get rid of parentheses

3x+4x-10-31-90=0

We add all the numbers together, and all the variables

7x-131=0

We move all terms containing x to the left, all other terms to the right

7x=131

x=131/7

x=18+5/7

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