(3x-10)+(54)+(5x+4)+(4x+4)+(144-4x)=360

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Solution for (3x-10)+(54)+(5x+4)+(4x+4)+(144-4x)=360 equation: 



(3x-10)+(54)+(5x+4)+(4x+4)+(144-4x)=360

We move all terms to the left:

(3x-10)+(54)+(5x+4)+(4x+4)+(144-4x)-(360)=0

We add all the numbers together, and all the variables

(3x-10)+(5x+4)+(4x+4)+(-4x+144)+54-360=0

We add all the numbers together, and all the variables

(3x-10)+(5x+4)+(4x+4)+(-4x+144)-306=0

We get rid of parentheses

3x+5x+4x-4x-10+4+4+144-306=0

We add all the numbers together, and all the variables

8x-164=0

We move all terms containing x to the left, all other terms to the right

8x=164

x=164/8

x=20+1/2

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