(3x-10)+(5x+20)=120

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Solution for (3x-10)+(5x+20)=120 equation: 



(3x-10)+(5x+20)=120

We move all terms to the left:

(3x-10)+(5x+20)-(120)=0

We get rid of parentheses

3x+5x-10+20-120=0

We add all the numbers together, and all the variables

8x-110=0

We move all terms containing x to the left, all other terms to the right

8x=110

x=110/8

x=13+3/4

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