(3x-10)=(4x+20)

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Solution for (3x-10)=(4x+20) equation:



(3x-10)=(4x+20)
We move all terms to the left:
(3x-10)-((4x+20))=0
We get rid of parentheses
3x-((4x+20))-10=0
We calculate terms in parentheses: -((4x+20)), so:
(4x+20)
We get rid of parentheses
4x+20
Back to the equation:
-(4x+20)
We get rid of parentheses
3x-4x-20-10=0
We add all the numbers together, and all the variables
-1x-30=0
We move all terms containing x to the left, all other terms to the right
-x=30
x=30/-1
x=-30

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