(3x-100)+(x-10)+(x-10)=180

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Solution for (3x-100)+(x-10)+(x-10)=180 equation: 



(3x-100)+(x-10)+(x-10)=180

We move all terms to the left:

(3x-100)+(x-10)+(x-10)-(180)=0

We get rid of parentheses

3x+x+x-100-10-10-180=0

We add all the numbers together, and all the variables

5x-300=0

We move all terms containing x to the left, all other terms to the right

5x=300

x=300/5

x=60

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