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(3x-12)(-5x+10x)=0
We add all the numbers together, and all the variables
(3x-12)(+5x)=0
We multiply parentheses ..
(+15x^2-60x)=0
We get rid of parentheses
15x^2-60x=0
a = 15; b = -60; c = 0;
Δ = b2-4ac
Δ = -602-4·15·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-60}{2*15}=\frac{0}{30} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+60}{2*15}=\frac{120}{30} =4 $
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