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(3x-12)(4x-2)=0
We multiply parentheses ..
(+12x^2-6x-48x+24)=0
We get rid of parentheses
12x^2-6x-48x+24=0
We add all the numbers together, and all the variables
12x^2-54x+24=0
a = 12; b = -54; c = +24;
Δ = b2-4ac
Δ = -542-4·12·24
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-54)-42}{2*12}=\frac{12}{24} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-54)+42}{2*12}=\frac{96}{24} =4 $
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