(3x-12)+(4x+20)=113

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Solution for (3x-12)+(4x+20)=113 equation: 



(3x-12)+(4x+20)=113

We move all terms to the left:

(3x-12)+(4x+20)-(113)=0

We get rid of parentheses

3x+4x-12+20-113=0

We add all the numbers together, and all the variables

7x-105=0

We move all terms containing x to the left, all other terms to the right

7x=105

x=105/7

x=15

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