(3x-12)+(x+30)+(2x)=180

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Solution for (3x-12)+(x+30)+(2x)=180 equation: 



(3x-12)+(x+30)+(2x)=180

We move all terms to the left:

(3x-12)+(x+30)+(2x)-(180)=0

We add all the numbers together, and all the variables

2x+(3x-12)+(x+30)-180=0

We get rid of parentheses

2x+3x+x-12+30-180=0

We add all the numbers together, and all the variables

6x-162=0

We move all terms containing x to the left, all other terms to the right

6x=162

x=162/6

x=27

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