(3x-12)+x=48

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Solution for (3x-12)+x=48 equation: 



(3x-12)+x=48

We move all terms to the left:

(3x-12)+x-(48)=0

We add all the numbers together, and all the variables

x+(3x-12)-48=0

We get rid of parentheses

x+3x-12-48=0

We add all the numbers together, and all the variables

4x-60=0

We move all terms containing x to the left, all other terms to the right

4x=60

x=60/4

x=15

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