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(3x-12)/(5x+4)=12
We move all terms to the left:
(3x-12)/(5x+4)-(12)=0
Domain of the equation: (5x+4)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
5x!=-4
x!=-4/5
x!=-4/5
x∈R
(3x-12)-12*(5x+4)=0
We multiply parentheses
(3x-12)-60x-48=0
We get rid of parentheses
3x-60x-12-48=0
We add all the numbers together, and all the variables
-57x-60=0
We move all terms containing x to the left, all other terms to the right
-57x=60
x=60/-57
x=-1+1/19
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