(3x-12)=(x+64)

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Solution for (3x-12)=(x+64) equation: 



(3x-12)=(x+64)

We move all terms to the left:

(3x-12)-((x+64))=0

We get rid of parentheses

3x-((x+64))-12=0



We calculate terms in parentheses: -((x+64)), so:

(x+64)

We get rid of parentheses

x+64

Back to the equation:

-(x+64)



We get rid of parentheses

3x-x-64-12=0

We add all the numbers together, and all the variables

2x-76=0

We move all terms containing x to the left, all other terms to the right

2x=76

x=76/2

x=38

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