(3x-12/3x)/x-4

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Solution for (3x-12/3x)/x-4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(3*x-((12/3)*x))/x-4 = 0

(3*x-4*x)/x-4 = 0

-x/x-4 = 0

(-4*x)/x-x/x = 0

-x-4*x = 0

-5*x = 0

(-5*x)/x = 0

(-5*x)/x = 0 // * x

-5*x = 0

-5*x = 0 // : -5

x = 0

x in { 0} 

x belongs to the empty set

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