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(3x-14)(2x+10)=180
We move all terms to the left:
(3x-14)(2x+10)-(180)=0
We multiply parentheses ..
(+6x^2+30x-28x-140)-180=0
We get rid of parentheses
6x^2+30x-28x-140-180=0
We add all the numbers together, and all the variables
6x^2+2x-320=0
a = 6; b = 2; c = -320;
Δ = b2-4ac
Δ = 22-4·6·(-320)
Δ = 7684
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7684}=\sqrt{4*1921}=\sqrt{4}*\sqrt{1921}=2\sqrt{1921}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{1921}}{2*6}=\frac{-2-2\sqrt{1921}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{1921}}{2*6}=\frac{-2+2\sqrt{1921}}{12} $
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