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(3x-14)(9x+20)=0
We multiply parentheses ..
(+27x^2+60x-126x-280)=0
We get rid of parentheses
27x^2+60x-126x-280=0
We add all the numbers together, and all the variables
27x^2-66x-280=0
a = 27; b = -66; c = -280;
Δ = b2-4ac
Δ = -662-4·27·(-280)
Δ = 34596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{34596}=186$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-186}{2*27}=\frac{-120}{54} =-2+2/9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+186}{2*27}=\frac{252}{54} =4+2/3 $
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