(3x-15)=(3x+25)4x

Solution for (3x-15)=(3x+25)4x equation:

(3x-15)=(3x+25)4x

We move all terms to the left:

(3x-15)-((3x+25)4x)=0

We get rid of parentheses

3x-((3x+25)4x)-15=0


We calculate terms in parentheses: -((3x+25)4x), so:

(3x+25)4x

We multiply parentheses

12x^2+100x

Back to the equation:

-(12x^2+100x)


We get rid of parentheses

-12x^2+3x-100x-15=0

We add all the numbers together, and all the variables

-12x^2-97x-15=0

a = -12; b = -97; c = -15;
Δ = b2-4ac
Δ = -972-4·(-12)·(-15)
Δ = 8689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-97)-\sqrt{8689}}{2*-12}=\frac{97-\sqrt{8689}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-97)+\sqrt{8689}}{2*-12}=\frac{97+\sqrt{8689}}{-24}
$