(3x-15)=(8x+8)+(2x+18)

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Solution for (3x-15)=(8x+8)+(2x+18) equation: 



(3x-15)=(8x+8)+(2x+18)

We move all terms to the left:

(3x-15)-((8x+8)+(2x+18))=0

We get rid of parentheses

3x-((8x+8)+(2x+18))-15=0



We calculate terms in parentheses: -((8x+8)+(2x+18)), so:

(8x+8)+(2x+18)

We get rid of parentheses

8x+2x+8+18

We add all the numbers together, and all the variables

10x+26

Back to the equation:

-(10x+26)



We get rid of parentheses

3x-10x-26-15=0

We add all the numbers together, and all the variables

-7x-41=0

We move all terms containing x to the left, all other terms to the right

-7x=41

x=41/-7

x=-5+6/7

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