(3x-17)+(x+40)=(2x-5

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Solution for (3x-17)+(x+40)=(2x-5 equation: 



(3x-17)+(x+40)=(2x-5

We move all terms to the left:

(3x-17)+(x+40)-((2x-5)=0

We get rid of parentheses

3x+x-((2x-5)-17+40=0

We add all the numbers together, and all the variables

4x-((2x-5)-17+40=0

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