(3x-17)+x+40+(2x-5)=180

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Solution for (3x-17)+x+40+(2x-5)=180 equation: 



(3x-17)+x+40+(2x-5)=180

We move all terms to the left:

(3x-17)+x+40+(2x-5)-(180)=0

We add all the numbers together, and all the variables

x+(3x-17)+(2x-5)-140=0

We get rid of parentheses

x+3x+2x-17-5-140=0

We add all the numbers together, and all the variables

6x-162=0

We move all terms containing x to the left, all other terms to the right

6x=162

x=162/6

x=27

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