(3x-18)(8x+)=0

Solution for (3x-18)(8x+)=0 equation:

(3x-18)(8x+)=0

We add all the numbers together, and all the variables

(3x-18)(+8x)=0

We multiply parentheses ..

(+24x^2-144x)=0

We get rid of parentheses

24x^2-144x=0

a = 24; b = -144; c = 0;
Δ = b2-4ac
Δ = -1442-4·24·0
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-144)-144}{2*24}=\frac{0}{48}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-144)+144}{2*24}=\frac{288}{48}
=6
$