(3x-2)(-2x+16)=0

Solution for (3x-2)(-2x+16)=0 equation:

(3x-2)(-2x+16)=0

We multiply parentheses ..

(-6x^2+48x+4x-32)=0

We get rid of parentheses

-6x^2+48x+4x-32=0

We add all the numbers together, and all the variables

-6x^2+52x-32=0

a = -6; b = 52; c = -32;
Δ = b2-4ac
Δ = 522-4·(-6)·(-32)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(52)-44}{2*-6}=\frac{-96}{-12}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(52)+44}{2*-6}=\frac{-8}{-12}
=2/3
$