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(3x-2)(2x+1)=143
We move all terms to the left:
(3x-2)(2x+1)-(143)=0
We multiply parentheses ..
(+6x^2+3x-4x-2)-143=0
We get rid of parentheses
6x^2+3x-4x-2-143=0
We add all the numbers together, and all the variables
6x^2-1x-145=0
a = 6; b = -1; c = -145;
Δ = b2-4ac
Δ = -12-4·6·(-145)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3481}=59$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-59}{2*6}=\frac{-58}{12} =-4+5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+59}{2*6}=\frac{60}{12} =5 $
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