(3x-2)(2x+3)=2x(3x+1)+18

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Solution for (3x-2)(2x+3)=2x(3x+1)+18 equation: 



(3x-2)(2x+3)=2x(3x+1)+18

We move all terms to the left:

(3x-2)(2x+3)-(2x(3x+1)+18)=0

We multiply parentheses ..

(+6x^2+9x-4x-6)-(2x(3x+1)+18)=0



We calculate terms in parentheses: -(2x(3x+1)+18), so:

2x(3x+1)+18

We multiply parentheses

6x^2+2x+18

Back to the equation:

-(6x^2+2x+18)



We get rid of parentheses

6x^2-6x^2+9x-4x-2x-6-18=0

We add all the numbers together, and all the variables

3x-24=0

We move all terms containing x to the left, all other terms to the right

3x=24

x=24/3

x=8

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