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(3x-2)(2x+3)=2x(3x+1)+18
We move all terms to the left:
(3x-2)(2x+3)-(2x(3x+1)+18)=0
We multiply parentheses ..
(+6x^2+9x-4x-6)-(2x(3x+1)+18)=0
We calculate terms in parentheses: -(2x(3x+1)+18), so:We get rid of parentheses
2x(3x+1)+18
We multiply parentheses
6x^2+2x+18
Back to the equation:
-(6x^2+2x+18)
6x^2-6x^2+9x-4x-2x-6-18=0
We add all the numbers together, and all the variables
3x-24=0
We move all terms containing x to the left, all other terms to the right
3x=24
x=24/3
x=8
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