(3x-2)(3x+2)=300

Solution for (3x-2)(3x+2)=300 equation:

(3x-2)(3x+2)=300

We move all terms to the left:

(3x-2)(3x+2)-(300)=0

We use the square of the difference formula

9x^2-4-300=0

We add all the numbers together, and all the variables

9x^2-304=0

a = 9; b = 0; c = -304;
Δ = b2-4ac
Δ = 02-4·9·(-304)
Δ = 10944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{10944}=\sqrt{576*19}=\sqrt{576}*\sqrt{19}=24\sqrt{19}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{19}}{2*9}=\frac{0-24\sqrt{19}}{18}
=-\frac{24\sqrt{19}}{18}
=-\frac{4\sqrt{19}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{19}}{2*9}=\frac{0+24\sqrt{19}}{18}
=\frac{24\sqrt{19}}{18}
=\frac{4\sqrt{19}}{3}
$