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(3x-2)(4x-11)=0
We multiply parentheses ..
(+12x^2-33x-8x+22)=0
We get rid of parentheses
12x^2-33x-8x+22=0
We add all the numbers together, and all the variables
12x^2-41x+22=0
a = 12; b = -41; c = +22;
Δ = b2-4ac
Δ = -412-4·12·22
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-25}{2*12}=\frac{16}{24} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+25}{2*12}=\frac{66}{24} =2+3/4 $
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