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(3x-2)(5x-1)=0
We multiply parentheses ..
(+15x^2-3x-10x+2)=0
We get rid of parentheses
15x^2-3x-10x+2=0
We add all the numbers together, and all the variables
15x^2-13x+2=0
a = 15; b = -13; c = +2;
Δ = b2-4ac
Δ = -132-4·15·2
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-7}{2*15}=\frac{6}{30} =1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+7}{2*15}=\frac{20}{30} =2/3 $
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