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(3x-2)(6x+9)=0
We multiply parentheses ..
(+18x^2+27x-12x-18)=0
We get rid of parentheses
18x^2+27x-12x-18=0
We add all the numbers together, and all the variables
18x^2+15x-18=0
a = 18; b = 15; c = -18;
Δ = b2-4ac
Δ = 152-4·18·(-18)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-39}{2*18}=\frac{-54}{36} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+39}{2*18}=\frac{24}{36} =2/3 $
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