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(3x-2)(7x+1)=0.
We multiply parentheses ..
(+21x^2+3x-14x-2)=0
We get rid of parentheses
21x^2+3x-14x-2=0
We add all the numbers together, and all the variables
21x^2-11x-2=0
a = 21; b = -11; c = -2;
Δ = b2-4ac
Δ = -112-4·21·(-2)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-17}{2*21}=\frac{-6}{42} =-1/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+17}{2*21}=\frac{28}{42} =2/3 $
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