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(3x-2)(x+3)=4x-7
We move all terms to the left:
(3x-2)(x+3)-(4x-7)=0
We get rid of parentheses
(3x-2)(x+3)-4x+7=0
We multiply parentheses ..
(+3x^2+9x-2x-6)-4x+7=0
We get rid of parentheses
3x^2+9x-2x-4x-6+7=0
We add all the numbers together, and all the variables
3x^2+3x+1=0
a = 3; b = 3; c = +1;
Δ = b2-4ac
Δ = 32-4·3·1
Δ = -3
Delta is less than zero, so there is no solution for the equation
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