(3x-2)+(3x+1)+(10x-11)=180

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Solution for (3x-2)+(3x+1)+(10x-11)=180 equation: 



(3x-2)+(3x+1)+(10x-11)=180

We move all terms to the left:

(3x-2)+(3x+1)+(10x-11)-(180)=0

We get rid of parentheses

3x+3x+10x-2+1-11-180=0

We add all the numbers together, and all the variables

16x-192=0

We move all terms containing x to the left, all other terms to the right

16x=192

x=192/16

x=12

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