(3x-2)+(4x+7)=8x-12

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Solution for (3x-2)+(4x+7)=8x-12 equation: 



(3x-2)+(4x+7)=8x-12

We move all terms to the left:

(3x-2)+(4x+7)-(8x-12)=0

We get rid of parentheses

3x+4x-8x-2+7+12=0

We add all the numbers together, and all the variables

-1x+17=0

We move all terms containing x to the left, all other terms to the right

-x=-17

x=-17/-1

x=+17

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