(3x-2)+(5x-4)=10

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Solution for (3x-2)+(5x-4)=10 equation: 



(3x-2)+(5x-4)=10

We move all terms to the left:

(3x-2)+(5x-4)-(10)=0

We get rid of parentheses

3x+5x-2-4-10=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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