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(3x-2)+(9x-13)=x+1
We move all terms to the left:
(3x-2)+(9x-13)-(x+1)=0
We get rid of parentheses
3x+9x-x-2-13-1=0
We add all the numbers together, and all the variables
11x-16=0
We move all terms containing x to the left, all other terms to the right
11x=16
x=16/11
x=1+5/11
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