(3x-2)+(x-1)+(x+3)=180

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Solution for (3x-2)+(x-1)+(x+3)=180 equation: 



(3x-2)+(x-1)+(x+3)=180

We move all terms to the left:

(3x-2)+(x-1)+(x+3)-(180)=0

We get rid of parentheses

3x+x+x-2-1+3-180=0

We add all the numbers together, and all the variables

5x-180=0

We move all terms containing x to the left, all other terms to the right

5x=180

x=180/5

x=36

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